Running Sum of 1d Array
Description
Given an array nums
. We define a running sum of an array as runningSum[i] = sum(nums[0]…nums[i])
.
Return the running sum of nums
.
Example 1:
Input: nums = [1,2,3,4] Output: [1,3,6,10] Explanation: Running sum is obtained as follows: [1, 1+2, 1+2+3, 1+2+3+4].
Example 2:
Input: nums = [1,1,1,1,1] Output: [1,2,3,4,5] Explanation: Running sum is obtained as follows: [1, 1+1, 1+1+1, 1+1+1+1, 1+1+1+1+1].
Example 3:
Input: nums = [3,1,2,10,1] Output: [3,4,6,16,17]
Constraints:
1 <= nums.length <= 1000
-10^6 <= nums[i] <= 10^6
Solution(javascript)
/**
* @param {number[]} nums
* @return {number[]}
*/
var runningSum = function(nums) {
let runningSum = 0;
let runningSumArray = [];
for (let i = 0; i < nums.length; i++) {
runningSum += nums[i]
runningSumArray[i] = runningSum
}
return runningSumArray;
};